Cumulants of integrated variance under a fast regime
The fourth cumulant of a return whose CIR variance has a fast switching level, and what its Green–Kubo form leaves out at every maturity.
The model
A stationary finite-state chain $Y_t$ switches the long-run level of a square-root (CIR) variance:
$$dv_t=\kappa(\theta(Y_t)-v_t)\,dt+\xi\sqrt{v_t}\,dB_t, \qquad v_0>0.$$The Brownian motion $B$ is independent of $Y$ and of the price Brownian motion. We keep $\kappa$ and $\xi$ fixed and assume $2\kappa\min_i\theta_i\ge\xi^2$, so the variance stays strictly positive.
The integrated variance is $V_T=\int_0^T v_s\,ds$. With $Z$ a standard normal independent of it, the Brownian return and the risk-neutral log return are
$$M_T = \sqrt{V_T}\,Z, \qquad X_T = -\tfrac12 V_T + \sqrt{V_T}\,Z.$$Leverage, a correlation between the price and variance Brownian motions, is taken up below.
The quantity
The cumulants of $V_T$, $M_T$ and $X_T$. Conditional normality gives the cumulant-generating functions
$$K_M(z)=K_V(z^2/2), \qquad K_X(z)=K_V((z^2-z)/2),$$and comparing coefficients proves the exact identities
The last two formulas are not interchangeable. The expression $3\operatorname{Var}(V_T)$ is exact for the martingale return $M_T$, but the drift $-V_T/2$ of the log return is random too, and its third and fourth cumulants enter.
The exact variance of integrated variance
Write
$$B_\kappa(t)=\frac{1-e^{-\kappa t}}{\kappa}, \qquad \bar\theta=\mathbb E_\pi\theta(Y_0),$$ $$C_m(u)=\operatorname{Cov}_\pi(\theta(Y_0),\theta(Y_u)), \qquad K_m=\int_0^\infty C_m(u)\,du.$$Integrating the CIR equation and then integrating over time splits $V_T$ into a regime integral and a martingale, and the two are uncorrelated. Itô isometry gives the exact decomposition
The first line is the integrated-variance variance of the averaged CIR model, $\operatorname{Var}_{\rm av}(V_T)$. The second is exactly the extra variance created by the hidden regimes. This separation does not require an asymptotic expansion.
The Green–Kubo correction and a uniform bound
Put $I_2(T)=\int_0^T B_\kappa(s)^2\,ds$. Replacing the narrow correlation kernel by its mass $K_m$ gives
$$\operatorname{Var}(V_T)=\operatorname{Var}_{\rm av}(V_T) +2\kappa^2 K_m I_2(T)+R_V(T,m),$$and the remainder can be bounded without fixing the maturity:
If the generator is $mQ_0$ and $|C_m(u)|\le A e^{-m\rho u}$, the right side is at most $4A/(m^2\rho^2)$. Consequently
This is a finite-rate statement, uniform over all maturities.
A two-state check
The certificate uses a symmetric chain with flip rate $m$, $\theta=(0.08,0.02)$, $\kappa=2$, $\xi=0.2$, $v_0=0.04$, and $T=1.5$. Here $C_m(u)=0.03^2e^{-2mu}$ and $K_m=0.03^2/(2m)$. An independent matrix exponential for every mixed moment of total degree at most four agrees with the covariance decomposition to better than $2\times10^{-13}$.
| $m$ | exact $\kappa_4(M)$ | first order | residual | $m^2$ residual |
|---|---|---|---|---|
| 2 | 0.0019797681 | 0.0021728072 | −1.9304e-4 | −7.7216e-4 |
| 4 | 0.0015882057 | 0.0016333692 | −4.5164e-5 | −7.2262e-4 |
| 8 | 0.0013531018 | 0.0013636502 | −1.0548e-5 | −6.7510e-4 |
| 16 | 0.0012262720 | 0.0012287907 | −2.5187e-6 | −6.4479e-4 |
| 32 | 0.0011607479 | 0.0011613610 | −6.1309e-7 | −6.2780e-4 |
The scaled residual settles, confirming the $m^{-2}$ remainder.
Leverage
Now allow the price and variance Brownian motions to have correlation $\rho$. Conditional on the variance path, $M_T$ is no longer an independent centered normal with variance $V_T$. Write $\kappa_{r,s}$ for the joint cumulant with $r$ copies of $M_T$ and $s$ copies of $V_T$; multilinearity gives
For the certificate parameters at switching speed $m=8$, the independent shortcut is exact at $\rho=0$ but materially wrong under leverage:
| $\rho$ | exact $\kappa_4(X)$ | independent shortcut | error |
|---|---|---|---|
| 0 | 0.001362747 | 0.001362747 | 0 |
| −0.7 | 0.003433475 | 0.001362747 | +0.002070728 |
| +0.7 | 0.002649857 | 0.001362747 | +0.001287110 |
Positive and negative leverage do not give the same log-return kurtosis. At $\rho=-0.7$, the independence formula misses about 60% of the exact fourth cumulant.
Further results in the full note
Option prices. For a symmetric two-state chain with $\delta=(\theta_+-\theta_-)/2$ and any fixed correlation $\rho$, the Heston Riccati coefficient $B_s$ does not depend on the regime. At fixed maturity, uniformly for $s$ in any compact subset of the MGF strip,
Carr–Madan inversion turns this into a call correction $C_m(k)=C_{\rm av}(k)+c_1(k)/m+O(m^{-2})$. On compact strike sets where Black–Scholes Vega $\mathcal V_{\rm av}$ has a positive lower bound, the implied volatility is corrected by $b_1(k)/m$ with $b_1(k)=c_1(k)/\mathcal V_{\rm av}(k)$.
Positivity. Let the drift $c_i=\kappa_i\theta_i$, the mean reversion $\kappa_i$ and the vol-of-vol $\xi_i$ all switch. Zero is inaccessible from every positive initial value and every initial regime if
$$2c_i\ge\xi_i^2\qquad\text{for every }i,$$and for an irreducible finite chain this condition is also necessary. The Feller test cannot be applied only to the averaged model: a two-state example passes on average with $2\bar c/\overline{\xi^2}=1.6$, yet from $v_0=0.04$ in the deficient regime the exact probability of hitting zero before the next switch is $0.2341927683$.
Simultaneous switching. When $\kappa$ switches too, the averaged drift is $\bar c-\bar\kappa v$, whose effective mean level is $\bar c/\bar\kappa$, generally not $\bar\theta$. The first-order correction to the moments of $V_T$ through order four, and so to its cumulants, then holds at fixed maturity with an $O_T(m^{-2})$ remainder, and the dependence on $T$ is necessary. In a two-state example the long-run mean is
$$\mu_m=\frac{25m+13}{50(7m+4)} =\frac1{14}-\frac9{2450m}+\frac{18}{8575m^2}+O(m^{-3}),$$and $\mathbb E[V_T]=\mu_mT+O_m(1)$ as $T\to\infty$, so the residual left after the averaged and first-order slopes grows linearly in maturity for every fixed $m$. Retaining the exact slope $\mu_m$ and one slow exponential mode restores an $O(m^{-2})$ approximation to $\mathbb E[V_T]$ uniform over $T\ge0$.
Invariant moments. With $a_i=\xi_i^2$, the row vectors $r_i^{(p)}=\mathbb E_{\Pi_m}[v^p\mathbf1_{\{Y=i\}}]$ of the invariant law satisfy an exact triangular recursion:
All positive integer invariant moments are finite. This needs mean reversion, not the statewise Feller inequality.
Long maturities. Started in the joint invariant law, the variance of $V_T$ has an exact slope and intercept, each from finite linear solves, with an exponentially decaying remainder:
$$\operatorname{Var}_{\Pi_m}(V_T)=\sigma_m^2T+\chi_m+\rho_m(T).$$For every fixed integer $k\ge2$ and every fixed switching rate $m>0$ the limit $\lim_{T\to\infty}\kappa_k(V_T)/T$ exists and is given by a triangular recursion of Poisson equations.
The full note also covers explicit Green–Kubo forms of the slow mode, truncated slopes on growing maturity windows, uniform Gamma and cumulant-disk bounds for the invariant law, inverse-speed expansions of the invariant moments and long-run rates, arbitrary-start boundary constants, the transfer to independent and leveraged return cumulants, and standardized cumulants.
Scope
The chain starts in stationarity; a known or filtered starting regime adds an initial-memory term. The exact decomposition, the maturity-uniform bound and the call correction assume fixed $\kappa$ and switch only the CIR mean level. The maturity-uniform bound is proved for the independent-price benchmark; no maturity-uniform leverage bound is claimed.
The conditional integrated-variance viewpoint goes back to Hull and White (1987), and the finite-dimensional moment construction follows the polynomial-process framework of Cuchiero, Keller-Ressel and Teichmann (2012).
Proofs, further tables and references: the full note. Certificates: verify_cumulants.py, verify_switching_kappa.py, verify_switching_feller.py.